a polygon of n sides has n(n-3)/2 diagonals . how many sides a polygon with 54 diagonals
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0
Answer:
6 sides.................
Answered by
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Answer:
12 sides
Step-by-step explanation:
n(n - 3) ÷ 2 = 54
n(n - 3) = 108
n² - 3n - 108 = 0
= - 9 (not an answer for this task)
= 12
Given polygon has 12 sides.
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