Question

a polygon that can be divided into a triangle and a trapezium . the height of the triangle is sixty cm and the base is 11 cm . the hypotenuse of the triangle is one of the parallel sided of the trapezium , which is not given. another parallel side is 26 cm and the height of the trapezium is 18 cm , calculate the area of the polygon . ​

Answer 1

the length of the hypotenuse line will be=

square root of [11^2 + 60^2]

= square root of [121+3600]

= square root of [3,721]

= 61 cm

therefore:

the area of polygon = area of triangle + area of trapezium

area of triangle= 1/2*base*height

                         =1/2*60*11 = 330 cm2

and

area of trapezium= 1/2*(sum of parallel sides)*height

                             =1/2*(61+26)*18

                             =783 cm2

therefore:

area of the polygon = 330cm2+783cm2

                                 =1113cm2

if this answer helped you, mark me the brainliest

Answer 2

Answer:

I have pinned the answer image, you can check it

Hope you may get it

Mark as brainliest

Thank You...