Question

A polynomial –7x + 8 is a


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Answer 1

Hello friends☺️☺️

Here is your answer :

{x}^{2} + 7x - 8x

2

+7x−8

To find Zeroes

{x}^{2} + 7x - 8 = 0x

2

+7x−8=0

{x}^{2} + 8x - x - 8 = 0x

2

+8x−x−8=0

x(x + 8) - 1(x + 8) = 0x(x+8)−1(x+8)=0

(x + 8)(x - 1) = 0(x+8)(x−1)=0

x + 8 = 0 \: \: \: \: \: or \: \: \: \: x - 1 = 0x+8=0orx−1=0

x = - 8 \: \: \: \: or \: \: \: \: x = 1x=−8orx=1

Zeroes are - 8 and 1.

Sum of Zeroes :

\alpha + \beta = - 8 + 1α+β=−8+1

= - 7=−7

= \frac{ - (7)}{1}=

1

−(7)

= \frac{ - b}{a}=

a

−b

Product of Zeroes :

\alpha \beta = ( - 8)(1)αβ=(−8)(1)

= - 8=−8

= \frac{ - 8}{1}=

1

−8

= \frac{c}{a}=

a

c

Hence, verified.

Hope it helps you...