A polynomial in x of degree three vanishes when x= 1 and x = -2 and has the values 4 and 28 when x=-1 and x = 2 respectively, then f(1) is
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Answer:
0
Step-by-step explanation:
by substituting x values and solving equation (x-1).(x+2).(x-k)=0
we get k=-5 (by substituting x=2 and equating to 28)
as f(1) is also a root it is equal to 0 i think so
RajivNagar:
why you x=k not -k
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