A polynomial of degree 5 with leading coefficient 2 is such that P(1) = 1,P(2) = 4,P(3) = 9,P(4) = 16,P(5) = 25. Then the value of P(6) is
Anonymous:
I did it using the calculator on my tab. The answer I got is 276.
It required a lot of calculation, I found the determinants of order 5×5. Is this question really asked anywhere? Or is it a computer based problem?
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p(6)=36 is the answer
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Using Crammer's Rule and with the help of a computer, the answer I got is 276.
I'm sorry for not providing the calculation. Fell free to report or delete it.
I meant "feel" free to delete it.
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