Question

a polynomial p(x) is given as 2x²- 3kx+ 5one of the zeros of p(x) is -1 find k​

Answer 1

Answer:

k= -7/3

Step-by-step explanation:

p(x) = 2x²-3kx+5

one of the zeros of p(x) is -1

So, p(-1)= 0

2(-1)²-3k(-1)+5=0

2(1) -3k(-1) +5=0

2+3k+5=0

3k= -7

k= -7/3

Answer 2

Answer:

Given: p(x) = -1

To find k in the polynomial 2x^2 - 3kx +5

Sol:

Put the vaue of p(x) i.e; -1 in the given polynomial

= 2(-1)^2 - 3k(-1) +5 = 0

= -2+ 3k +5= 0

= 3+3k = 0

= 3=-3k

= k = -1