A pond has an ice layer of thickness 3 cm if k of ice is 0.005
Answers
The question seems to be incomplete, here is the complete question:
A pond has an ice layer of thickness 3 cm if k of ice is 0.005 CGS unit surface temperature of surroundings is - 20° Celsius, density of ice is 0.9 gm/cm the time taken for the thickness to increase by 1 cm is?
Answer:
a = surface area of ice layer
t will be the thickness and it will be 1 cm
The mass will be m
m = density x A x 1
= 0.9 x A x 1
= 0.9 A grams
The heat required will be:
Q = mL
= 0.9A x 80 = 72A Calories
The mean of the thickness will be :
d = 3 + 4/2 = 3.5 cm
The expression for Q would be:
Q = KAΔθt/d
t = Qd/KAΔθ
= 72A x 3.5 / 0.005 x A x 20
= 2520 s
If there is any confusion please leave a comment below.
Answer:
the time taken for the thickness to increase by 1 cm is 42 minutes