Question

A pool ball leaves a 0.6 m high table with an initial horizontal velocity of 2.4 m/s. Find the time required for the ball to fall to the ground and the horizontal distance between the table's edge and the ball's landing location.

Answer 1

Answer:

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Answer 2

Answer:

A billiards ball leaves a 0.6 m high table with an initial horizontal velocity of 2.4 m/s.What is the time required for the billiards ball to fall to the ground and the horizontal distance between the table's edge and the ball's landing location?

Assuming we are on earth or someplace where acceleration due to gravity is 9.8 m/s^2, the time to fall the distance, S, can be found by rearranging S= (1/2) a*t^2

sqrt(2S / a) = t = sqrt(2*0.6 / 9.8) = 0.35 s time to fall.

d = v*t = 2.4*0.35 = 0.84 m horizontal distance to ball hitting the ground.