Question

a pool is 20 m long. 15 m broad and 4m deep .find the cost of cementing its floor and its walls at the rate of rs. 12 per square meter​

Answer 1

Answer:₹696

Step-by-step explanation:

Area to be cemented=2(l+b)*h + lb

=2(20+15)*4 + 20*15

=8*35 +20*15

=280 + 300

=580 m²

Cost=580*12

=₹696

Plz mark me as the brainliast......

Answer 2

AnswEr :

⋆ Refrence of Image is in the Diagram :

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$\rule{150}{1}$

$\underline{\bigstar\:\textsf{Let's Head to the Question Now :}}$

$\dashrightarrow\:\:\texttt{Cost of Cementing = (CSA of Pool + Base) \times Rate}\\\\\\\dashrightarrow\:\:\tt Cost = \lbrack\{2(L+ B)H\} + (L \times B)\rbrack\times Rate\\\\\\\dashrightarrow\:\:\tt Cost =\lbrack \{2(20 \:m + 15 \:m) \times 4 \:m \} + (20 \:m \times 15 \:m)\rbrack \times Rs. \:12 \:m^{ - 2}\\\\\\\dashrightarrow\:\:\tt Cost =\lbrack \{2 \times 35 \:m\times 4 \:m \} + 300 \:{m}^{2} \rbrack \times Rs. \:12 \:m^{ - 2}\\\\\\\dashrightarrow\:\:\tt Cost =\lbrack280 \:m^{2} + 300 \:m^{2} \rbrack \times Rs. \:12 \:m^{ - 2}\\\\\\\dashrightarrow\:\:\tt Cost =580\:m^{2} \times Rs.\:12 \:m^{ - 2}\\\\\\\dashrightarrow\:\:\tt Cost =580 \times Rs.\:12\\\\\\\dashrightarrow\:\: \underline{\boxed{\tt Cost =Rs.\:6960}}$

⠀

$\therefore\:\underline{\textsf{Cost of cementing of walls is \textbf{Rs. 6960}}}.$