Math, asked by aanchal3247, 1 year ago

A pool is 20m long, 15 m broad and 4m deep, find the cost of cementing its floor and wall at the rate of Rs 17.50 per metre
Plzzz solve this question

Answers

Answered by Mukulsinghyadav
0
unhen the other hand on it is very much appreciated and then I think it might have the time and consideration in

aanchal3247: hey this is not the my Q's ans
Answered by Anonymous
8

Diagram :

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Solution :

\tt{Cost \: of \: Cementing = (CSA \: of \: Pool + Base) \times Rate}

\tt Cost = \lbrack\{2(L+ B)H\} + (L \times B)\rbrack\times Rate

\tt Cost =\lbrack \{2(20 \:m + 15 \:m) \times 4 \:m \} + (20 \:m \times 15 \:m)\rbrack \times Rs. \:17.50 \:m^{ - 2}

\tt Cost =\lbrack \{2 \times 35 \:m\times 4 \:m \} + 300 \:{m}^{2} \rbrack \times Rs. \:17.50 \:m^{ - 2}

\tt Cost =\lbrack280 \:m^{2} + 300 \:m^{2} \rbrack \times Rs. \:17.50 \:m^{ - 2}

\tt Cost =580\:\cancel{m^{2}} \times Rs.\:17.50 \:\cancel{m^{ - 2}}

\tt Cost =580 \times Rs.\:17.50

\tt Cost =580 \times Rs.\: \dfrac{1750}{100}

\tt Cost =58\cancel{0} \times Rs.\: \dfrac{175\cancel{0}}{1\cancel{0}\cancel{0}}

\tt Cost =58 \times Rs.\: 175

\tt Cost = Rs. \: 10150

\underline{\boxed{\tt Cost =Rs.\: 10150}}

\therefore \textsf{Cost of cementing of walls is Rs. 10150}

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