Question

A popular game in Indian villages is goli which is played with small glass balls called golis. The goli of one player is situated at a distance of 2.0 m from the goli of the second player. This second player has to project his goli by keeping the thumb of the left hand at the place of his goli, holding the goli between his two middle fingers and making the throw. If the projected goli hits the goli of the first player, the second player wins. If the height from which the goli is projected is 19.6 cm from the ground and the goli is to be projected horizontally, with what speed should it be projected so that it directly hits the stationery goli without falling on the ground earlier?

Answer 1

It should be projected at 10 m/s speed, so that it hits the stationary goli directly without falling on the ground earlier .

Explanation:

Step 1:

Given data in question :

The goli moves like a projectile, in this situation,

                Height (h) = 196 cm  

Cm to meter  :

                Height (h)  = $\frac{196}{100}=1.96 m$

                Horizontal distance = x = 2m

                a = g = 9.8m/s²

Step 2:

Time taken to get to earth =  $\sqrt{\frac{2 k}{g}}$

                                            $=\sqrt{\frac{2 \times 1.26}{9.8}}$

                                            $=\sqrt{\frac{302}{9.8}}$

                                            $=\sqrt{0.4}$

                                         T = 0.2 sec

Step 3:

Let the horizontal velocity it is projected with be u.

                         x = ut

                         $u=\frac{a}{t}$

                         $u=\frac{2}{0.2}$

                         $u=10 \mathrm{m} / \mathrm{s}$

Thus, the speed is, u = 10 m/s.