Question

A population consists of 6 elements which are R+2, R+2,R,R,R and R+3 draw all possible sample of size 3 Without replacement. Construct sampling distribution of sample proportion of odd numbers and find mean and Variance of the distribution.Also varify the result to the actual population.(R is 39)​

Answer 1

Sample sd = \sqrt{variance}

= \sqrt{3.3611}

= 1.833variance

=3.3611

=1.833

Variance= sd^2

= 3.42^2

= 11.67

\frac{\sigma }{{\sqrt n }}\sqrt {\frac{{N – n}}{{N – 1}}} = \frac{{3.42}}{{\sqrt 3 }}\sqrt {\frac{{6 – 3}}{{6 – 1}}}

= 1.529nσN–1N–n

=33.426–16–3

this is the answer.all solutions