Question

A population of a town increased by 10% annually if the present population is 60000 what will be its population after 2 years?

Answer 1

$\boxed{\bold{\large{Answer:}}}$

$\text{10\:percent\:of\:60000\:will\:be,}$

$\implies \: \frac{10}{100} \times 60000 = 6000$

$\text{After\:the\:population\:increased\:by\:10\:percent}$

$\implies60000 + 6000 = 66000 \\ \\ \implies \frac{10}{100} \times 66000 = 6600$

$\text{Increase\:in\:population\:after\:2\:years\:will\:be,}$

$\implies66000 + 6600 = 72600$

$\text{The\:population\:after\:2\:years\:will\:be\:72600}$

$\boxed{\bold{\large{Hope\:it\:helps\:you!}}}$

Answer 2

HEY MATE HERE IS YOUR ANSWER
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▶️ The present population :- 60000


➡️ 10% will be

$\frac{10}{100} \times {60000} = 6000$


Now, we calculate the population after increased by 10%

▶️ 60000 + 6000 = 66000

$\frac{10}{100} \times{66000} = 6600$

Increase in population after 2 years

➡️ 66000 + 6600 = 72600


Therefore, the population after 2 years is 72600.

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Hope it will help you