A population of bacteria is growing at a rate of 20% per hour. If the population starts at 320, what is it an hour later?
Answers
Answer:
384.
Step-by-step explanation:
The population is given by the expression;
Y(t) = Pr^{t}Y(t)=Pr
t
Where;
Y(t) is the number of bacteria at time, t.
P is the starting amount.
r is the growth rate.
Given that, P = 320, r = 20% = 0.2, t = 1
Substituting the parameters into the equation;
Y(t) = Pr^{t}Y(t)=Pr
t
Y(1) = 320 * 0.2¹
Y(1) = 320 * 0.2
Y(1) = 64.
Therefore, the population of bacteria increases hourly by 64.
An hour later; 320 + 64 = 384.
Answer:
374
Step-by-step explanation:
The population is given by the expression; Y (t) = Pr^t
Where;
Y (t) is the number of bacteria at time, t.
P is the starting amount.
r is the growth rate.
Given that , P = 320, r = 20% = 0.2, t = 1
Substituting the parameters in the equation;
Y (t) = Pr^t
Y (1) = 320* 0.2¹
Y (1) = 320* 0.2
Y (1) = 64.
Therefore, the population of bacteria increases hourly by 64.
An hour later; 320 + 64 = 384.