A porter lifts a luggage 15kg from the ground and puts it on his head 1.5m above the ground. Calculate the work done by him on the luggage.
Answers
Answered by
2
Answer:
work done = FS
F=mg
s=h
work = mgh
=15×10×1.5
=225joule
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Answered by
2
Explanation:
work = energy
Given:
mass,m=15kg
height,h=1.5m
gravitational acceleration,g=9.8m/s^2 or 10m/s^2
Available Formulas :
w=f×s
potential energy=mgh
kinetic energy=1/2mv^2
we have Mass height and gravitational acceleration therefore we use our second formula that is potential energy=mgh
here in the question it is not given to use g=10 therefore we will use g=9.8
work done = mgh
= 15×1.5×9.8
=22.5×9.8
=220.5 j
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