Question

A Porter lifts a luggage of 15 kg from the ground and put it on his head 1.5 m above the ground calculate the work done by him on the luggage

Answer 1

work done by the porter on the luggage =Force x displacement =mgh =15kg*(9.8m/s'2)*1.5m=220.5 j

Answer 2

Answer:

Answer:-

The work done by the Porter on the luggage \large\leadsto\boxed{\tt\purple{225 \: J}}⇝

225J

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• Given:-

Weight lifted by the Porter from the ground = 15 kg

Height of the luggage after placing it on the head = 1.5 m

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• To Find:-

The work done by the Porter on the luggage.

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• Solution:-

We know,

For work done,

$\pink{\bigstar}★ \large\underline{\boxed{\bf\blue{W = mgh}}}$

W=mgh

where,

W = Work done

m = mass of the body

g = acceleration due to gravity [10 ms-²]

h = height of the body

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• Substituting in the Formula:-

➪ =15×10×1.5

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➪ W=150×1.5

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➪ W = 225W=225

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✯ Unit of Work is Joules [J] .

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Hence,

$★ \large\underline{\underline{\bf\red{W = 225 \: J}}}$

W=225J

Therefore, the work done by the Porter on the luggage is 225 J.