Question

A porter lifts a luggage of 15
kg from the ground and puts it on his head 1.5 m above the ground. Calculate the work done by him on the luggage.
WITH STEP BY STEP EXPLANATION.
I WILL MARK AS BRAINLIEST WHO GIVE A PERFECT ANSWER.​
Answer soon

Answer 1

Answer:

Step-by-step explanation:

Mass of the luggage , m = 15 kg and

displacement , s = 1.5 m .

Work done , W = F × s = mg × s

= 15 kg × 10 m s-² × 1.5 m

= 225 kg m s-² m

= 225 N m = 225 J

work done is 225 J.

OR if this makes you understand more easily

Work done by the porter on the luggage = Force x displacement = mgh = 15 kg x (9.8 m/s2) x 1.5 m = 220.5 J

HOPE THIS HELPS YOU !!!!!

Answer 2

Given :-

Mass of the luggage = 15 kg

Height carried above the ground = 1.5 m

To Find :-

The work done by him on the luggage.

Analysis :-

Here we are given with the mass and height.

In order to find the work done, multiply the mass, gravity and height given in the question accordingly.

Solution :-

We know that,

• w = Work
• m = Mass
• g = Acceleration due to gravity
• h = Height

Using the formula,

$\underline{\boxed{\sf Work \ done=m \times g \times h}}$

Given that,

Mass (m) = 15 kg

Gravity (g) = 10 m/s

Height (h) = 1.5 m

Substituting their values,

⇒ 15 × 10 × 1.5

⇒ 225 J

Therefore, the work done by him on the luggage is 225 J.