Question

a porter lifts a luggage of 15kg from the ground and puts it on head 1.5m above the ground.calculate the work done by him on luggage​

Answer 1

Solution :

➡ Given:

✏ A porter lifts a luggage of 15kg from the ground and puts it on head 1.5m above the ground.

➡ To Find:

✏ The work done by him on luggage.

➡ Concept:

✏ As per work-energy theorem, work done is always equal to change in total energy of system.

$\star \: \underline{ \boxed{ \bold{ \sf{ \pink{ \large{Work\:done= \triangle{Energy}}}}}}} \: \star$

➡ Calculation:

$\implies \sf \: W = \triangle{Potential \: Energy} \\ \\ \implies \sf \: W = (PE)_{final}- (PE)_{initial} \\ \\ \implies \sf \: W = mg(h - 0) \\ \\ \implies \sf \: W = 15 \times 10 \times 1.5 \\ \\ \implies \underline{ \boxed{ \bold{ \sf{ \orange{ \large{Work \: done = 225 \: J}}}}}} \: \bigstar$

Answer 2

$\mathtt{ \huge{ \fbox{Solution :)}}}$

Given ,

• Mass (m) = 15 kg
• Inital height (h2) = 0 m
• Final height (h1) = 1.5 m

We know that ,

The work done is defined as the change in total energy of the system

$\large \mathtt{ \fbox{Work \: done = mg h_{1}- mgh_{2}}}$

Thus ,

Work done = 15 × 9.8(1.5 - 0)

Work done = 15 × 9.8 × 1.5

Work done = 220.5 joule

Hence , the work done is 220.5 joule

_____________ Keep Smiling ☺