Question

A porticle u dropped from
wpol bulding of height H.
find the time it take to
come to the ground its
velocity with which it
hits the ground.​

Answer 1

Explanation:

Therefore

H=(1/2) (gt^2)

$2h = g {t}^{2} \\ t {}^{2} = \frac{2h}{g} \\ t= \sqrt{ \frac{2h}{g} }$