Math, asked by mitamehta1974mm, 9 months ago

a portion of 6600 dollar is invested at a 5%annual return while the remainder is invested at 3%annual return. if the annual income from the portion earning a 5% return is twice that of the other portion,what is the total income from the two investments after one year.​

Answers

Answered by JackelineCasarez
6

$ 270 is the total income from the two investments after one year.​

Step-by-step explanation:

Let the first proportion be x,

so the other will be 6600 - x

Given that,

5% of first proportion = 5x/100

3% of second proportion = 3(6600-x) /100

A.T.Q.

Annual income from first proportion = Twice of other proportion

5x/100 = 2(3(6600-x)) /100

5x/100 = 2(19,800 - 3x)/100

5x = 39,600 - 6x

5x + 6x = 39600

11x = 39,600

x = 3600

∵ Total income from both the investments = 5(3600)/100 + 3(6600-3600)/100

= $ 270

Thus, option A is the correct answer.

Learn more: Calculate the Compound Interest

brainly.in/question/6762842

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