Question

A position vector of a particle is given by r(t) =(ti^ +3t j^+ 24k^ )m then magnitude of velocity at
t=2sec
​

Answer 1

Answer:

Magnitude of this vector is

Root t^2+9t^2 +576

Put t =2 sec.

Root 4+36+576

Root 616

24.81

That's your answer