A positive 3 digit number has its units digit zero. find the probability that the number is divisible by 4.
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total number of 3 digit number end with 0 = 90
total number of 3 digit number end with 0 that are divisible by 4 = 45
probability of getting 3 digit number end with 0 that are divisible by 4 =![\frac{45}{90} \frac{45}{90}](https://tex.z-dn.net/?f=+%5Cfrac%7B45%7D%7B90%7D+)
= 1/2
total number of 3 digit number end with 0 that are divisible by 4 = 45
probability of getting 3 digit number end with 0 that are divisible by 4 =
= 1/2
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