Question

A positive charge +2Q is located at point -3 m from the origin. What is the sign and size of the second charge Qx located at point 2 m from the origin, if the electric potential at the origin is zero?

Answer 1

The charge $Q_x$ is $\dfrac{4Q}{3}$ .

Given :

A positive charge +2 Q is located at point -3 m from the origin .

Let , charge of other particle be $Q_x$ .

It is also given that charge q is placed at 2 m from the origin .

Now ,

We know potential at a point is given by :

$V=\dfrac{kQ}{r}$  ( where k is a constant , Q is charge and r is distance from the point where potential is to be measure ).

It is also given that the sum to their potential is zero at origin .

$\dfrac{k(2Q)}{(-3)}+\dfrac{kQ_x}{2}=0\\\\Q_x=\dfrac{4Q}{3}$

Hence , this is the required solution .

Learn More :

Electrostatics

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