a positive charge of 20÷(3x10^(9))C is situated at a distance of 0.30 metre from negative charge of 30x(3x10^(9)) what is the potential at a point lying between the two charges on the straight line joining them at a distance of 0.10 from the first charge
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Explanation:
f 20÷(3x10^(9))C - 30x(3x10^(9))
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