Question

A positive charge q exerts a force of magnitude - 0.20 N on another charge - 2q. Find the magnitude of each charge if the distance separating them is equal to 50 cm.​

Answer 1

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Answer 2

$\huge\underline\mathfrak{\pink{ Solution }}$

The force that q exert on 2q is given by Coulomb's law:

F = k (q) ( - 2q) / r2 , r = 0.5 m , F = - 0.20 N ,

- 0.2 = - 2 q2 k / 0.52

q2 = 0.2 × 0.52 / (2 k)

q = √ [ (0.2 × 0.52 / (2 × 9 × 109) ] = 1.66 × 10-6 C

q = 1.66 × 10-6 C , -2 q = -3.23 × 10-6 C