Question

A positive charge q' is moved arround another positive charge q on a circular path if the radius of the circle is r the work done on the charge q' in making one complete evolution is?
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Answer 1

Explanation:

We know potential at distance r= kQ/r

Now voltage is constant as r is constant

We know work done w=Δv ⋅υ

⇒ w=0 as Δv=0

so the answer is 0

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Answer 2

Answer:qq'/2εo

εo is epsilon not

Explanation:

WORK DONE= FORCE*DISPLACEMENT

FORCE= kqq'/r^2 (r square)

distance between q and q'= r

displacement= 2πr^2(2pi r square)

work done = qq'*2πr^2/4πεo*r^2

i.e. qq'/2εo