Question

A positive charge (q) is released from rest in an electric field.of strength E .

The force experienced by the positive charge is ....................​

Answer 1

Electrostatic force ,F=qE⇒m

dt

dv

​

=qE

Integrating, we will get, v=

m

qE

​

t+c where c= integraing constant.

at t=0,v=0 , so c=0

now, v=

m

qEt

​

∴K.E=

2

1

​

mv

2

=

2m

q

2

E

2

t

2

​

Ans:(C)

Answer 2

Explanation:

Electrostatic force ,F=qE⇒m

dt

dv

=qE

Integrating, we will get, v=

m

qE

t+c where c= integraing constant.

at t=0,v=0 , so c=0

now, v=

m

qEt

∴K.E=

2

1

mv

2

=

2m

q

2

E

2

t

2

Ans:(C)