A positive integer is twice another. The sum of the reciprocals of the two positive integers is 3/8. Find the two integer.
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Answer:
The integers are 1)The smaller number =x= 2/root of 3.
2)The other number is=2x=2X2/root of 3 =4/root of 3
Step-by-step explanation:
let the smaller one be x
while the other be 2x
sum of reciprocal of the two numbers =3/8
hence,
1/x + 1/2x=3/8
1/2x^2=3/8
1/x^2=3X2/8
taking reciprocal
x^2=8/6
x^2=4/3
The smaller number =x= 2/root of 3
hence,
The other number is=2x=2X2/root of 3 =4/root of 3
this is not sure
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