a positive integer n has five digits. N is six digit number obtained by adjoining 2 as the leftmost digit of n. M is the six digit number by adjoining 2 at the right must digit of n. If M = 3N, find all the values of n.
Answers
Answer: 85714
Step-by-step explanation: this is pretty much trial and error method, didnt come up with anything extraordinary, (will take 5-7 min max)
285714*3=857142
positive integer = 85714 become 3 times if 2 is adjoined in right to the number if 2 is adjoined in left
Step-by-step explanation:
let say five digit number
abcde
N is number obtained by adjoining 2 as the leftmost digit of n
N = 2abcde
M is the six digit number by adjoining 2 at the right must digit of n
M = abcde2
M = 3N
=> abcde2 = 3 * 2abcde
3*e end with 2 hence e = 4
=> abcd42 = 3 * 2abcd4
3d + 1 ends with 4 ( 1 carried forward from 3 * 4)
hence d = 1
=> abc142 = 3 * 2abc14
3c ends with 1 => c = 7
=> ab7142 = 3 * 2ab714
3* b + 2 end with 7 ( 2 carried forward from 3 * 7)
=> b = 5
=> a57142 = 3 * 2a5714
3a + 1 = 5 ( 1 carried forward from 3 * 5)
=> a = 8
=> 857142 = 3 * 285714
positive integer = 85714
The sum of two digit number formed by interchanging the digit
https://brainly.in/question/8039460