Math, asked by agrima3077, 1 year ago

A positive integer 'n' is such that it's only digits are 3's. 'n'is exactly divisible by 383. When n/383 is divided by 1000, what is the remainder?
A. 351
B. 781
C. 651
D. 931

Answers

Answered by franktheruler
8

Answer:

Option (C), 651 is the correct answer.

Step-by-step explanation:

383 and 1000 are relatively prime because 383 has no factors of 2 or 5.

Doing so gives (383)^(-1) = 47 (mod 1000). We can see that 383*47 = 18001 = 1 (mod 1000).

A number n whose digits are 3's which is divisible by 383 should be larger than 333.

So, n mod 1000 = 333.

Now

(n/383) mod 1000

= (n * (383)^(-1)) mod 1000

= 333 * 47 mod 1000

= 15651 mod 1000

= 651

Answered by krrew
5

Answer:

651

Step-by-step explanation:

383 and 1000 are relatively prime because 383 has no factors of 2 or 5.

Doing so gives (383)^(-1) = 47 (mod 1000). We can see that 383*47 = 18001 = 1 (mod 1000).

A number n whose digits are 3's which is divisible by 383 should be larger than 333.

So, n mod 1000 = 333.

Now

(n/383) mod 1000

= (n * (383)^(-1)) mod 1000

= 333 * 47 mod 1000

= 15651 mod 1000

= 651

Similar questions