A positive integer n when divided by 9,gives 7 as remainder what will be the remainder when (3n-1)is divided by ?
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Hi ,
********************************************
By Division algorithm :
Divided = quotient × divisor + remainder
********************************************
According to the problem given ,
If n is divided by 9 , Let the quotient
is x , remainder is 7
n = 9x + 7----( 1 )
Multiply ( 1 ) with 3 , we get
3n = 27x + 21
Subtract 1 both sides of the equation ,
we get
3n - 1 = 27x + 21 - 1
3n - 1 = 27x + 20
3n - 1 = 9 × 3x + 20
Therefore ,
If ( 3n - 1 ) divided by 9 , the
remainder is 20
I hope this helps you.
: )
********************************************
By Division algorithm :
Divided = quotient × divisor + remainder
********************************************
According to the problem given ,
If n is divided by 9 , Let the quotient
is x , remainder is 7
n = 9x + 7----( 1 )
Multiply ( 1 ) with 3 , we get
3n = 27x + 21
Subtract 1 both sides of the equation ,
we get
3n - 1 = 27x + 21 - 1
3n - 1 = 27x + 20
3n - 1 = 9 × 3x + 20
Therefore ,
If ( 3n - 1 ) divided by 9 , the
remainder is 20
I hope this helps you.
: )
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