Question

A positive integer n when divided by 9, gives
7 as remainder. What will be the remainder
when (3n - 1) is divided by 9?
(A) 1 (B) 2 (C) 3 (D) 4​

Answer 1

Answer:

The smallest no. which when divided by 9 gives remainder 7 is the no.16

Therefore, take n=16.

Now, (3n-1)/9= (3×16-1)/9

= (48-1)/9

= 47/9

when 9 divides 47, it leaves a remainder 2.