Math, asked by hawabazi7581, 9 months ago

A positive integer 'x' on division by 7 leaves remainder 5. Find the remainder when 4x+31 is divided by 14.

Answers

Answered by parag28
2

Answer:

the remainder is 9

Step-by-step explanation:

the step by step answer is given in diagram

Attachments:
Answered by TanikaWaddle
0

The required remainder is 9

Step-by-step explanation:

given :A positive integer 'x' on division by 7 leaves remainder 5.

i.e

dividend = divisor × quotient +remainder

x= 7k+5

to find the remainder when 4x+31 is divided by 14.

i.e

4x +31 = 4(7k+5) +31

4x+31 = 28k+20+31

4x+31 =28k+51 ..(1)

now , from equation 1

when 28 is divided by 14 , the remainder is 0

when 51 is divided by 14 , the remainder is 9

thus  , the remainder when 4x+31 is divided by 14 is 9

hence , The required remainder is 9

#Learn more :

The set of all positive integers which leaves remainder 5 when divided by 7 are​

https://brainly.in/question/16047201

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