A positive number is 5 times another no. If 21 is added to both the number became twice of other new no..find the original no.
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Answer:
35/7
Step-by-step explanation:
Let the number be x
other number y
x=5y
(x+21)=2(y+21)
substitute x as 5y
5y+21=2y+42
3y=21
y=7
x=35
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