Question

A positive number is 5 times another number. If 21 is added to both the numbers than one of the new numbers become twice the other new number. What are the numbers?

Answer 1

Step-by-step explanation:

let greater number be x

and smaller number be y

x = 5y

x - 5y = 0...............(1)

x +21 = 2(y +21)

x + 21 = 2y + 42

x - 2y = 21.............(2)

(2) - (1) =>

x - 2y = 21

x - 5y = 0

- +

__________

3y = 21

y = 7

Put (y = 7) in (1)

x -5y = 0

x = 5y

x = 5(7)

x = 35

So, two numbers are 35 and 7 respectively...

Answer 2

SOLUTION:-

Given:

•A positive number is 5 times another number.

•If 21 is added to both the numbers than one of the new number become twice the other new number.

To find:

The number.

Explanation:

Let the positive number be 5R.

Let the another number be R.

•On adding 21 to both number;

Positive number is 5R + 21

Another number is R +21.

According to the question:

=) 2[R+21]= 5R +21

=) 2R + 42 = 5R +21

=) 2R -5R = 21 -42

=) -3R = -21

=) R= -21/-3

=) R= 7

Thus,

The positive number is 5R=5×7= 35

Another number is R= 7.