Question

A positive number is 5 times another number. If 21 is added to both the numbers then one of the new numbers becomes twice the other new number. what are the numbers?​

Answer 1

Answer:

let one of the number be x

second number be 5x

2(x+21)=(5x+21)

=> 2x+42=5x+21

=> 2x−5x=21−42

=> −3x=−21

x=7

One of the number 7

Second number 7×5=35

Step-by-step explanation:

Answer 2

$\bf{\Huge{\underline{\boxed{\sf{\green{ANSWER\::}}}}}}$

$\bf{\Large{\underline{\sf{\orange{Given\::}}}}}$

A positive number is 5 times another number. If 21 is added to both the numbers then one of the new number becomes twice the other new number.

$\bf{\Large{\underline{\sf{\red{To\:find\::}}}}}$

The number.

$\bf{\Large{\underline{\sf{\blue{Explanation\::}}}}}$

Let the other number be R

We have,

A positive number is 5 times another number.

∴ Positive number be 5R

A/q

21 added to both the given number, we get;

• New other number = R + 21
• New positive number = 5R + 21

One of the new number becomes twice the other new number;

→ 5R + 21 = 2(R + 21)

→ 5R + 21 = 2R + 42

→ 5R - 2R = 42 - 21

→ 3R = 21

→ R = $\bf{\cancel{\frac{21}{3} }}$

→ R = 7

Thus,

• Another number is,[R] = 7
• Positive number is,[5R] = (5 × 7) = 35