Question

A positive number is 5 times another number. If 21 is added to both the numbers,
then one of the new numbers becomes twice the other new number. What are the numbers? ​

Answer 1

${ \blue{ \tt{ \underline{ \underline{ \huge{QUESTION }}}}}}$




▪ A positive number is 5 Times another number. if 21 is added to both the numbers , then one of the new numbers become twice the other new number. what are the numbers?




${ \blue{ \tt{ \huge{ \underline{ \underline{SOLUTION }}}}}}$




Let the two positive numbers be x and y respectively....


given that..

⛦ a number is 5 Times the other number



${ \boxed{ \red{ \sf{x = 5y}}}} - - - { \sf{eqn(1)}}$



${ \sf{ \underline{according \: to \: the \: question - }}}$



▪ If 21 is added to both the numbers



one of the new number become twice of the new number.....



${ \boxed{ \red{ \sf{(x + 21) = 2(y + 21)}}}}$



${ \implies{ \green{ \sf{x + 21 = 2y + 42}}}}$



putting the value of x = 5y from eqn (1)..



${ \implies{ \sf{ \green{5y + 21 = 2y + 42}}}}$



${ \implies{ \sf{ \green{5y - 2y = 42 - 21}}}}$



${ \implies{ \sf{ \green{3y = 21}}}}$



${ \implies{ \boxed{ \boxed{ \red{ \sf{ \: \: \: y = 7 \: \: }}}}}}$



${ \boxed{ \boxed{ \sf{ \red{x = 5y = 5 \times 7 = 35}}}}}$



therefore,



the numbers are 35 and 7

Answer 2

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