Question

. A positive number is 5 times another number. If 21 is added to both the numbers, then one of the new numbers becomes twice the other new number. What are the numbers? Pls ans this ques with solving./././././ Fastest and correct answer would be marked as brainliest

Answer 1

$let \: one \: no. \: be \: x \: and \: other \: no. \: be \: y. \\ x = 5y \: (eqn \: 1) \\ if \: 21 \: is \: added \: to \: both \: no.s \: then \\ x + 21 = 2(y + 21) \\ x + 21 = 2y + 42 \\ from \: eqn \: 1 \\ 5y + 21 = 2y + 42 \\ 5y - 2y = 42 - 21 \\ 3y = 21 \\ y = \frac{21}{3} \\ y = 7 \\ put \: in \: eqn \: 1 \\ x = 5(7) \\ x = 35$

First no. = x = 35

Other no. = y = 7

.

.

.

.

.

.

.

.

.

Mark as brainliest!!!