Question

a positive number is 5 times another number. if 21 is added to both the numbers, then one of the new numbers becomes twice the other new number. what are the numbers?

Answer 1

let the 1st no. is x
and the 2nd no. is 5x
A|S
2(x+21)=5x+21
2x+42=5x+21
x=7
1st no. is 7
and 2nd no. is 35

Answer 2

HELLO DEAR,

case (1)


let the one no. be x

then another no. be x/5


case(2)

(21+x)=2(x/5+21)

$(21 + x) = 2( \frac{x}{5} + 21) \\ = > 21 + x = \frac{2(x + 105)}{5} \\ = > 105 + 5x = 2x + 210\\ = > 5x - 2x = 210 - 105 \\ = > 3x = 105 \\ = > x = \frac{105}{3} \\ = > x = 35$
and another no. be 35/5=7



I HOPE ITS HELP YOU DEAR,
THANKS