Question

A positive number is 5 times another number . If 21 is added to both the numbers , then one of the new number become twice of another new numbers. Find the original numbers?

Answer 1

Answer:

The Numbers are 7 and 35

Step-by-step explanation:

Let the the smaller number be x and therefore the other number will be 5x.

Now according to the questions: 5x + 21 = 2(x + 21)

5x + 21 = 2(x + 21)

or  5x + 21 = 2x + 42

or 5x - 2x = 42 - 21

or 3x = 21

or x = 21/3 = 7

If x = 7 then 5x = 5*7 = 35

Therefore the original numbers were 7 & 35

Answer 2

$\large\underline{\underline \red{\bigstar{\textbf{\textsf{\: question\::-}}}}}$

A positive number is 5 times another number . If 21 is added to both the numbers , then one of the new number become twice of another new numbers. Find the original numbers?

$\large\underline{\underline \red{\bigstar{\textbf{\textsf{\: given\::-}}}}}$

A positive number is 5 times another number . If 21 is added to both the numbers , then one of the new number become twice of another new numbers..

$\large\underline{\underline \red{\bigstar{\textbf{\textsf{\: to \: find\::-}}}}}$

the original numbers?

$\large\underline{\underline \red{\bigstar{\textbf{\textsf{\: solution\::-}}}}}$

let the other number be X

given that, a positive number is 5 times that number therefore positive number = 5x

now, 21 added to both number therefore new number = X + 21

so therefore new number = 5x + 21

now according to question

$\sf ⇝5x + 21 = 2(x + 21)$

$\sf ⇝ \: 5x \: + 21 \: = 2x \: + 42$

$\sf ⇝5x - 2x + 21 = 42$

$\sf ⇝3x + 21 = 42$

$\sf ⇝3x = 21$

$\sf ⇝x = \cancel \frac{21}{3}$

$\sf ⇝x = 7$

so therefore anthore number is 7

positive number is 5 × 7 = 35