a positive number is 5 times another number . If 21 is added to both the numbers, then one of the new number becomes twice the other new number. What are the numbers?
Answers
Answered by
6
Let the first number be a
Second number = 5a
According to question,
5a + 21 = 2 ( a + 21)
=> 5a + 21 = 2a + 42
=> 3a = 21
=> a = 7
First number = 7
Second number = 7 × 5 = 35
Second number = 5a
According to question,
5a + 21 = 2 ( a + 21)
=> 5a + 21 = 2a + 42
=> 3a = 21
=> a = 7
First number = 7
Second number = 7 × 5 = 35
Tanishks:
how come 7
because we have considered the first number as 'a'
By solving the given condition
I got it thanks
Answered by
1
let the numbers be x and 5
if 21 is added to the numbers they would be,
5x+21,x+21
according to the problem the new number is twice the other number,
i.e 5x+21=2(x+21)
=5x+21=2x+42
5x-2x=42-21
3x=21
x=7
checking
let x=7
l.h.s
5*7+21
=35+21
=56
r.h.s
2*7+42
=14 +42
=56
if 21 is added to the numbers they would be,
5x+21,x+21
according to the problem the new number is twice the other number,
i.e 5x+21=2(x+21)
=5x+21=2x+42
5x-2x=42-21
3x=21
x=7
checking
let x=7
l.h.s
5*7+21
=35+21
=56
r.h.s
2*7+42
=14 +42
=56
one number is x =6
other number is 5x=5*7=35
sorry forgot to send in a hurry
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