Question

A positive number is 5times another number.If21 is added to both the numbers,then one of the new numbers becomes twice the other new number.what are the numbers? Answer: Let the number be X and 5x 21 is added to both the numbers X+21and5x+21 One of the new number becomes twice the other number 5x+21=2(X+21) (I want answer after this )

Answer 1

GIVEN:

• A positive number is 5 times another number.
• 21 is added to both the numbers,then one of the new numbers becomes twice the other new number.

TO FIND:

• What are the numbers ?

SOLUTION:

CASE:- 1)

❐ A positive number is 5times another number.

According to question:-

Let one number be 'x' and another number be '5x'

CASE:- 2)

❐ 21 is added to both the numbers,then one of the new numbers becomes twice the other new number.

According to question:-

New number :-

• (x + 21)
• (5x + 21)

➨ 5x + 21 = 2(x + 21)

➨ 5x + 21 = 2x + 42

➨ 5x –2x = 42 –21

➨ 3x = 21

➨ $\sf{ x = \cancel\dfrac{21}{3}}$

❮ x = One number = 7 ❯

Put the value of 'x' in another number

➨ Another number = 5x

➨ Another number = 5 $\times$ 7

❮ Another number = 35 ❯

❝ Hence, the one number is 7 and another number is 35 ❞

______________________

Answer 2

Solution :

Let the first number be a & second number be 5a

A/q

∴ Adding to both the number's :

$\longrightarrow\sf{2(a+21 )= 5a+21}\\\\\longrightarrow\sf{2a+42=5a+21}\\\\\longrightarrow\sf{2a-5a=21-42}\\\\\longrightarrow\sf{-3a=-21}\\\\\longrightarrow\sf{a=\cancel{-21/-3}}\\\\\longrightarrow\bf{a=7}$

Thus;

One number be a = 7

Other number be 5a = 5 × 7 = 35