A positive number is divided into two parts such that the sum of the squares of the two parts is 208. The square of the larger part is 18 times the smaller part. Taking x as the smaller part of the two parts, find the number.
Answers
Answer:
20
Step-by-step explanation:
Let the smaller and larger of two parts be x and y. According to question,
y2 = 18x
Sum of the squares of the two parts is 208.
x2 + y2 = 208
x2 + 18x - 208 = 0
x2 + 26x - 8x + 208 = 0
x(x + 26) - 8(x + 26) = 0
(x - 8)(x + 26) = 0
x = 8 or x = -26 (rejected as part of pice never be negative)
y = √18x
=√18 x 8
= √144
= 12
Hence, the no. is 8 + 12 = 20
Answer:
20
Step-by-step explanation:
Let the smaller and larger of two parts be x and y. According to question,
y2 = 18x
Sum of the squares of the two parts is 208.
x2 + y2 = 208
x2 + 18x - 208 = 0
x2 + 26x - 8x + 208 = 0
x(x + 26) - 8(x + 26) = 0
(x-8)(x + 26) = 0
x = 8 or x = -26 (rejected as part of pice never be negative)
y = √18x
=√18 x 8
= √144
= 12
Hence, the no. is 8 + 12 = 20