A positive number is divided into two parts such that the sum of the squares of the two parts is 208.The square of the larger part is 8 times the smaller part. Taking x as smaller part of the two parts,find the number.
plz ASAP
Answers
Answered by
6
✌hey mate here is your answer
let the smaller part be X
and larger part is y
so from first condition
x²+y²=208......(1)
and by second condition
y²=8x........(2)
put equation 2 in 1
x²+8x=208
x²+8x-208=0
by Hindu method
d=b²-4ac
=64+832
=896
X=(-b+_√d)/2a
=-8+-√896/2
so X=(-8+-8√14)/2
=8(-1+-√14)/2
=-4+-4√14
X=-4+4√14 or X=-4-4√14
✌hope it will help you
✌mark me brainliest
let the smaller part be X
and larger part is y
so from first condition
x²+y²=208......(1)
and by second condition
y²=8x........(2)
put equation 2 in 1
x²+8x=208
x²+8x-208=0
by Hindu method
d=b²-4ac
=64+832
=896
X=(-b+_√d)/2a
=-8+-√896/2
so X=(-8+-8√14)/2
=8(-1+-√14)/2
=-4+-4√14
X=-4+4√14 or X=-4-4√14
✌hope it will help you
✌mark me brainliest
siddhartharao77:
Read the question carefully. In the question it is given that A positive number is divided into two numbers.The answer will be an whole number..I have mentioned the correct question also!
no vampire002's answer is correct... it is not compulsory that the answer should be a whole number
sir also if there will be 308 in place of 208 then answer can also come
I have solved this kind of question already..It will be 18 in place of 8. times. One more thing is it was asked to find a number not two numbers. The numbers should be positive only!
but i m having the same answer in answer key as vamipe002's answer
sry to say but i am in favour of Siddhartharao77
Dont trust your book answers. Read the question carefully u will find the logic. @1Sehaj1
now i feel i will get failed in tomorrow's exam
best of luck
basically the question itself is wrong..... the square of the larger part is 18 times the smaller part not 8 times so then the value of x would be 8 and the larger part would 12 and the required number wouldve been 20. end of story.
Answered by
4
Answer:
4[ (-1) +(√14) ] +2√2×√(-4+4√14)
Step-by-step explanation:
let the smaller part be x
let the square of the larger part be 8x
acc. to question,
8x + x²=208
x²+8x-208=0
a=1, b=8, c= -208
using quadratic formula,
-b ±√b² - 4ac/ 2a
-8±√8²-4(1)(-208)/2(1)
-8±√896/2
-8±8√14/2
-4±4√14
x= -4+√14 (or) x = -4-√14 (rejected)
∴ x= -4+4√14 -- [1]
square of the larger part= 8x= 8( -4+4√14)
∴ larger part=2√2×√(-4+4√14) --[2]
[1] + [2] we get ,
the required number= 4[ (-1) +(√14) ] +2√2×√(-4+4√14)
This is a pretty complex answer!
hope it'll be useful!!
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