A Positive number, when decreased by 4 is equal to 21 times of the reciprocal 0f the number. find the number
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Let the positive number be x
Accordingto problem
x-4=21×1/x
x-4=21/x
x^2-4x=21
x^2-4x-21=0
x^2+3x-7x-21=0
x (x+3)-7 (x+3)=0
(x-7)(x+3)=0
x-7=0 (or) x+3=0
x=7 (or) x=-3
Therefore x=7 since -3 is an negative integer
____________________________
HOPE IT HELPS
Accordingto problem
x-4=21×1/x
x-4=21/x
x^2-4x=21
x^2-4x-21=0
x^2+3x-7x-21=0
x (x+3)-7 (x+3)=0
(x-7)(x+3)=0
x-7=0 (or) x+3=0
x=7 (or) x=-3
Therefore x=7 since -3 is an negative integer
____________________________
HOPE IT HELPS
Answered by
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