Question

A positive point charge 50 uc is located in the xy plane at a point with position vector r0=2i+3j

Answer 1

Plz write a complete question.
A complete question is ------->A point charge of 50μC is located in the x-y plane at the position vector r1 = (2i+3j)m. The electric field at the point of postion vector r = (8i-5j)m, in vector form is equal to ?

Solution :- separation vector = r - r₁
= 8i - 5j - (2i + 3j)
= 6i -8j
Magnitude of separation vector = |r - r₁| = √{6² + (-8)²} = 10 unit
∴ electric field , E = Kq/|r - r₁|²
Here, k = 9 × 10⁹ , q = 50 × 10⁻⁶ and |r - r₁| = 10
Now, E = 9 × 10⁹ × 50 × 10⁻⁶/100
= 4500 N/C

Answer 2

Answer:

Explanation:

Plz write a complete question.

A complete question is ------->A point charge of 50μC is located in the x-y plane at the position vector r1 = (2i+3j)m. The electric field at the point of postion vector r = (8i-5j)m, in vector form is equal to ?

Solution :- separation vector = r - r₁

= 8i - 5j - (2i + 3j)

= 6i -8j

Magnitude of separation vector = |r - r₁| = √{6² + (-8)²} = 10 unit

∴ electric field , E = Kq/|r - r₁|²

Here, k = 9 × 10⁹ , q = 50 × 10⁻⁶ and |r - r₁| = 10

Now, E = 9 × 10⁹ × 50 × 10⁻⁶/100

= 4500 N/C

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