Physics, asked by rohitnair1724, 6 months ago

a positive point charge q is kept near a charged plate , draw the electric field lines of forces from poiint charge to plate and derive an expression for the electric field intensity at the surface of the plate

Answers

Answered by ankushs
1

Answer:

Draw the electric field lines of forces from point charge to the plate. Derive an expression for the electric field intensity at the surface of the plate. . 1. See answer ... Add your answer and earn points.

Answered by TaimurHossain
2

Explanation:

Electric field intensity is the strength of an electric field at any point. It is equal to the electric force per unit charge experienced by a test charge placed at that point, or E=qF

From Gauss law, considering a spherical surface with charge at its center as Gaussian surface,

E(A)=ϵ0q

⟹E(4πr2)=ϵ0q

⟹E=4πϵ0r2q

which is the intensity of electric field at a distance r from the charge.

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