A positive point charge (+q) is kept near a charged plate.
(i) Draw the electric field lines of forces from point charge to
the plate.
(ii)Derive an expression for the electric field intensity at the
surface of the plate.
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Answer:
Electric field intensity is the strength of an electric field at any point. It is equal to the electric force per unit charge experienced by a test charge placed at that point, or E=
q
F
From Gauss law, considering a spherical surface with charge at its center as Gaussian surface,
E(A)=
ϵ
0
q
⟹E(4πr
2
)=
ϵ
0
q
⟹E=
4πϵ
0
r
2
q
which is the intensity of electric field at a distance r from the charge.
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