Question

A positive real number is 6 less than another. If the sum of the squares of the two numbers is 42, find the numbers.

Answer 1

Answer:

let one no be x

then another be x-6

a/q

(x) sq +( x-6)sq =42

x sq +x sq +36 =42

2x sq =6

x sq = 3

x =√3

first no =√3 another no=√3-6