Question

a poster is on top of a building. Rajesh is standing on the ground at a distance of 50 m from the building. The angles of elevation to the top of the poster and bottom of the poster are 45 and 30 respectively. What is the height of the poster

Answer 1

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Answer 2

Answer:

The height is $\frac{50}{\sqrt{3} } m$.

Step-by-step explanation:

It is given that a poster is on top of a building. Rajesh is standing on the ground at a distance of $50 m$ from the building.

The angles of elevation to the top of the poster and bottom of the poster are $45$ and $30$ degrees.

We need to determine height of building.

Hence base is $50m$.

As the angle of elevation of bottom of poster is actually from top of building.

Let height of building be $h$.

So, we can say that $tan 30=\frac{h}{50}$

$h=50*\frac{1}{\sqrt{3} }$

So the height is $\frac{50}{\sqrt{3} } m$.

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